n^2+100=-20n

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Solution for n^2+100=-20n equation: 



n^2+100=-20n

We move all terms to the left:

n^2+100-(-20n)=0

We get rid of parentheses

n^2+20n+100=0

a = 1; b = 20; c = +100;
Δ = b2-4ac
Δ = 202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-20}{2}=-10$

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